Lenses affect the light that passes through them making an image of the object from which the light waves come. Sometimes this image is real (you can form it on a surface such as a piece of paper) and sometimes virtual (it cannot be formed on a surface)
The radius of curvature
(R) of a surface is taken as a positive number if it increases the curvature of the waves – i.e.
converges the waves and negative if it decreases the curvature of the ways – i.e. diverges
the waves.
A surface that converges a wavefront is taken a positive e.g. a convex
lens
A surface that diverges a wavefront is taken as negative e.g. a concave
lens
When
light waves fall on a curved surface that surface changes the curvature of the wave. Lenses
are made with at least one curved surface (convex or concave) and so lenses simply change
the curvature of the waves that fall on them.
Therefore:
A lens adds curvature to a wavefront. As the waves enter the lens their curvature is changed. In the example below they are bent from a plane wave to form a converging wave in the lens. This wave is further converged when it leaves then lens.
You can
follow this change of curvature as the waves meet the lens and then pass through it,
emerging at the other side.
As the wave hits the lens it is the centre of the wave that
meets the glass first and so this part of the wave is slowed down first (light waves move
slower in glass than they do in air). This means that the outer portions of the wave 'catch up'
so increasing the curvature to form a converging beam.
As the wave leaves the lens
the outer portions move into the air first and so speed up first. This means that the outer
portions move off more rapidly first and so the curvature of the wave is further increased so
converging the light more strongly.
The overall action of the convex lens is therefore
to converge light waves to a focus.
Looking at the diagram you can see that waves
with no curvature have been converged to a point a distance f (the focal length) from the
lens. This means that they have been given a curvature 1/f. The shape of the incident waves
have no effect on how much the lens changes their curvature and so we can say that a lens
increases the curvature of waves that pass through it by a constant amount
1/f.
(Remember that 1/f will be positive for a convex lens and negative for a concave
lens)
The example has been done with a plane wave but the same would occur with
a spherical wave spreading outwards from a point
object.
Wavefronts spreading outwards from a point
source are taken as having a negative curvature and so the distance from the lens to the
object is negative
Wavefronts that converge to an image are taken as having a positive
curvature and so the distance from the lens to the image is positive.
The curvature of the waves spreading outwards towards a lens from an object distance u from the lens have a curvature 1/u and those converging to a point image on the other side of the lens have a curvature 1/v. The lens adds a constant curvature (1/f) to the wave and so the equation relating the object distance (u) image distance (v) and the focal length (f) is: